Then, the surface area of the surface of revolution formed by revolving the graph of g(y) around the y − axis is given by Surface Area = ∫d c(2πg(y)√1 (g′ (y))2dy Example 644 Calculating the Surface Area of a Surface of Revolution 1 Let f(x) = √x over the interval 1, 4 We start with the graph of y = f(x) graph{sqrt(16x^2) 326, 3234, 118, 7} We then will do two different transformations to this graph—a dilation, and a translation The 3 next to f(x) is a multiplier It tells you to stretch f(x) vertically by a factor of 3 That is, every point on y = f(x) gets moved to a point that's 3 times higherSketch the graph of the function f(x,y)= sqrt(16 x^2 16y^2) and explain Best Answer Previous question Next question Get more help from Chegg Solve it
Graph The Functions Below F X Y X2 Y2 Chegg Com
